Yes, it can do. But I don't quite understand Frans' remark that there's no
problem if the resistor fails.=0AIf that happened you would have no power?
=0AGraham=0A=0A=0A=0A=0A________________________________=0A From: Fred Klei
n <fklein@orcasonline.com>=0ATo: europa-list@matronics.com =0ASent: Sunday,
19 January 2014, 17:05=0ASubject: Re: Europa-List: Ammeters & Voltmeters
=0A =0A=0A=0A=0A=0AOn Jan 19, 2014, at 8:48 AM, GRAHAM SINGLETON wrote:=0A
=0AYou can measure current by noting the voltage drop across a short length
of=0A>wire, very small drop in the case of the main buss but still measura
ble.=0A>Then, Amps equals Volts divided by Resistance=0A>=0A=0AGraham...OK.
..but doesn't that all happen within the amp meter?...if I understand Frans
correctly, he's calling for the addition of a resistor in the line back at
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