What I meant was to measure the voltage drop across the length of the main
buss from=0Athe battery to where the alternator feeds in. You will get +ve
or _ve readings according to =0Acharging or discharging. A small milliamete
r will work and can be callibrated in Amps.=0AGraham=0A=0A=0A=0A=0A________
________________________=0A From: Pete Lawless <pete@lawless.info>=0ATo: eu
ropa-list@matronics.com =0ASent: Sunday, 19 January 2014, 17:27=0ASubject:
RE: {Fraud?} {Disarmed} Re: Europa-List: Ammeters & Voltmeters=0A =0A=0A=0A
=0AHi Fred=0A=C2-=0AIf you want it to =98happen=99 in=0Athe
amp meter then you need a great thick wire all the way to and from the amp
=0Ameter. =C2-Heavy and best avoided in my view.=0A=C2-=0AI think Graha
m means a short bit of wire=0Awith known resistance. =C2-=0A=C2-=0APres
umably one could connect a resistance=0Ain parallel down at the battery and
get the data across that?=C2- No sure of=0Athe maths on that idea but is
should be possible and would be fail safe.=0A=C2-=0APete=0AG-RMAC Classi
c 912 UL (volt meter only no=0Aamp meter)=0A=C2-=0A-----Original Message-
----=0AFrom: owner-europa-list-server@matronics.com=0A[mailto:owner-europa-
list-server@matronics.com] On Behalf Of Fred Klein=0ASent: 19 January 2014
17:05=0ATo: europa-list@matronics.com=0ASubject: {Fraud?} {Disarmed} Re:=0A
Europa-List: Ammeters & Voltmeters=0A=C2-=0A=C2-=0AOn Jan 19, 2014, at
8:48 AM, GRAHAM SINGLETON wrote:=0A=0A=0AYou can=0Ameasure current by notin
g the voltage drop across a short length of=0Awire, very small drop in the
case of the main buss but still measurable.=0AThen, Amps equals Volts divid
ed by Resistance=0A=C2-=0AGraham...OK...but doesn't that all happen withi
n the amp meter?...if I=0Aunderstand Frans correctly, he's calling for the
addition of a resistor in the=0Aline back at the battery...(?)...Fred=0A=C2
-http://www.matronics.com/Navigator?Europa-List=0AHouxou MailScanner has
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