Bruno, It is easy enough to work out next time you go
flying. Just throttle right back and measure height loss
in a timed minute at speeds around 70 kts. Or you can get
a rough answer by seeing what your rate of descent settles
out at on the VSI for a given speed and knowing that 100s
of feet per minute is much the same as knots you can
divide your airspeed (say 70 kts) by the descent speed
(say 550 fpm) to give 70/5.5 =12.7, that is a glide ratio
of 1:12.7. You may feel that you need a stopped prop to
give you a proper answer, but a stopped prop is thought to
have slightly less drag than a slowly rotating one so the
actual figures would be slightly better than your
computations. For what its worth my XS mono does around
1:12 at speeds between 65 and 75 kts. The optimum glide
angle is unaffected by weight, it just happens at a
slightly higher speed if you are heavy. So the answer to
the 2500ft Q is around 5.6 statute miles/4,9nm, further if
you turn down wind. Having said all that my advice would
be to forget about calculating such things and concentrate
on flying the plane - there are a lot too many stall spin
accidents in such circumstances!
Regards, David Joyce, G-XSDJ
"UVTREITH" <uvtreith@t-online.de> wrote:
> Hi Family
>
>
>
> Is there some information about the glide ratio of the
>Monowheel XS (and
> TriGear) by maximum take off weight with or without
>extended flaps?
>
> It would helpful to know by engine failure or other nice
>happenings how far
> I can fly (glide) with standing prop at say 2500 feet
>before I kiss the
> ground.
>
> I have checked all available leaflets, brochures etc,
>but could find
> nothing.
>
>
>
> Information about this would be very helpful.
>
> Nice and safe flights to all,
>
>
>
> Bruno
>
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